Model IsValid

Question

User1979860870 posted

Hi

  How the below 2 lines works in the below code

1.    return Json(new { success = true });
2.   return Json(phone, JsonRequestBehavior.AllowGet);

[HttpPost]
public JsonResult Create(Phone phone)
{
    if (ModelState.IsValid)
    {
        db.Phones.Add(phone);
        db.SaveChanges();
        return Json(new { success = true });
    }
    return Json(phone, JsonRequestBehavior.AllowGet);
}

Thanks

Answer 1

User475983607 posted

jagjit saini

Hi

  How the below 2 lines works in the below code

1.    return Json(new { success = true });
2.   return Json(phone, JsonRequestBehavior.AllowGet);

[HttpPost]
public JsonResult Create(Phone phone)
{
    if (ModelState.IsValid)
    {
        db.Phones.Add(phone);
        db.SaveChanges();
        return Json(new { success = true });
    }
    return Json(phone, JsonRequestBehavior.AllowGet);
}

Thanks

Pretty simple.  The unknown "Phone" type in JSON format is return when the model is invalid.  Otherwise, phone is added to the DbContext, saved and { success = true } is returned.

There is nothing stopping you from running this code your the Visual studio debugger.  The AllowGet is unnecessary since the Action is defined as a POST.  Plus the logic should check if phone exists before adding a new record.

Answer 2

User-1545767719 posted

  return Json(phone, JsonRequestBehavior.AllowGet);

why don't you use:

return View(phone);

?